((t^2-9)/3t)(18/(6t-18))

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Solution for ((t^2-9)/3t)(18/(6t-18)) equation: 


D( t )

6*t-18 = 0

6*t-18 = 0

6*t-18 = 0

6*t-18 = 0 // + 18

6*t = 18 // : 6

t = 18/6

t = 3

t in (-oo:3) U (3:+oo)

t*((t^2-9)/3)*(18/(6*t-18)) = 0

(18*t*(t^2-9))/(3*(6*t-18)) = 0

( t )

t = 0

( t^2-9 )

1*t^2 = 9 // : 1

t^2 = 9

t^2 = 9 // ^ 1/2

abs(t) = 3

t = 3 or t = -3

t in { 3} 

t in { 0, -3 }

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